Are you using the diodes that came with the kit? a diode MAKES electricity flow in ONE direction. For example in the first schematic, there is a diode between the relay and hot wire. Volts travel from NEGITIVE to POSITIVE That hot wire is linked to the switch and relay. if that diode isn't hooked up, then you'll have a voltage going straight to constant power or the (hot when ign is on wire) instead of to the switch and cause a CONSTANT draw Cause if that is not hooked up, then the switch could be off but volts will still travel and cause a draw. Now volts travel from NEGITIVE to POSITVE, so if your fuse blows, volts travel through the resistor stright to your LED it cant go through the diode, so it will illuminate the LED because that is hooked to another positive source, so obviously it will light up your LED. Plus you have something called OHMS LAW. in this circuit OHMS LAW reads I=E\R or current = volts\ resistance. there are 12 volts and 2k ohms of resistance 12\2k = 6mA if your diode is hooked up wrong, it will increase the amperage, cause a draw, and possibly short your fuse. The switch also causes resistance in the circuit, that resistance will help prevent draws, and shorts in fuses because current is flowing through extra loades cutting the current load on the fuse and possibly preventing it to blow. If the relay is hooked up wrong or backwards, when volts is applied, the relay could short, or toggle in a different direction other than the to where it's supposed to toggle to let current flow correctly. So, if I were you, I would use the diodes, hook the diodes up correctly, use the switch, and make sure your relay is hooked up correctly. The numbers on the schematic are referance numbers on the relay. So double check your relay. Plus if you have your ground LED hooked up, then you could test your grounds by hooking the clip of a testlight to a positive source, and probing your grounds. If the light doesn't light, then there is a bad GROUND connection. Hope that helps a little bit.